My first program using ιx → xSK combinator
Program:
(cdr (cons [x] [y])) translates to ((((ι(ι(ι(ιι))))(((ι(ι(ι(ιι))))(ιι))((ι(ι(ιι)))[x])))((ι(ι(ιι)))[y]))((ι(ι(ιι)))(ιι)))
using the ι combinator.
It evaluates to [y] just like its LISP equivalent.
Program:
(cdr (cons [x] [y])) translates to ((((ι(ι(ι(ιι))))(((ι(ι(ι(ιι))))(ιι))((ι(ι(ιι)))[x])))((ι(ι(ιι)))[y]))((ι(ι(ιι)))(ιι)))
using the ι combinator.
It evaluates to [y] just like its LISP equivalent.
.. and now and forever there is only,
ιx → xSK
Everything else is an illusion.
I had mistakingly thought Sambar is an -dimensional vector where
is the number of ingredients because, if one mixes 2 Sambars, the result is a Sambar. And if one takes a lot of Sambar, the result is Sambar too.
But I overlooked the fact that, each of the ingredients (basis vectors) of Sambar must be Sambar too, if it has to be a vector. For example, toovar dal (pigeon pea) must be considered Sambar too, own its own, without water or any other ingredients.
More over, no Sambar must be Sambar too. Because null vectors are part of a vector space.
So I was wrong..